## 2009년 9월 1일 화요일

### PJ step 5. value 1 n one third (2) /baduk/

At this post, more detailed explanations, so more dia.
White 1 sequence, there is nothing. (W)
Black 1 sequence. If black places A, there are 3 black crosses.
So, if there is not ending game bigger than this*, white must respond.
( *2 n one third I think. It's almost unusual anyway. )
Now white responded.
Can black go other side?
If black goes other side, white will do ponuki and you ought to remember second dia - there is noting. But here, white do ponuki. - So, black can't go other side.
So, this is a set of black 1 sequence. (X)
If black 1 sequence more, there are 2 black crosses include of 1 dead stone. (Y)
3 sequences ( W, X, Y ) make 2 crosses, so each 1 sequence makes two thirds.
Now, black 2 sequences ( X, Y ) make 1 and one third, but there are 2 crosses, so at first, there already exists two thirds black cross.
Got it? It may be difficult.

Conclusion 1 : Exist two thirds black cross in first dia.
White 1 sequence, there is two thirds black cross because of 1 minus one third. ( remember dead stone ) (Z)
Because W, X, Y are the same, and there is two thirds black cross, so Z is as well.

And, as you know, black and white has same right. ( so, two thirds multiple 2 )

Conclusion 2 : W, X, Y, Z has value of 1 n one third.

Not yet, to be continued.

#### 댓글 3개:

1. I think I understood :-)

2. Could you explain about dia Z, how to calculate W1 move value ?

3. step 4 may be the best answer.
It is equal to step 4.

more explanation for you,
at first, there is B two thirds, and black 1 sequence X, and white 1 sequence Z, and there is still B two thirds.
two thirds + X - Z = two thirds ?
X = Z
X value is 1 n one third.
So, Z value is too.