CR step 5. ES v.s NES /baduk/

There are eye-space-group and non-eye-space-group.
And, there is not in-space.
If there is not in-space, eye is meaningless. ( It's very important! )
So, at this dia, they have two out-spaces each other.
( In case of white, out-space 1 + eye-space-NUMBER 1 = 2 out-spaces for convenience' sake. )

But, there is an in-space.
It's defferent.
A is a burden of black. ( burden of NES )

 So, imagine that x marks are filled with any stone.
( One in-space matches one NES out-space )

Like this.
It's easy way to count. How about you?
If you do not agree, see the next dia.

It has many many many spaces.

But, if you use my "offsetting method", it can be easy.
White has 8 out-spaces ( out-spaces 3 + eye-space-number 5 = 8. )
Black has 9 out-spaces.
So, black will wins the race 1 sequence gap.